1.
[tex]F_{d} = \frac{mv^{2}}{r}\\\\v_1 = 2v\\r_1 = 2r\\\\F_{d_1} = \frac{m(2v)^{2}}{2r} = \frac{4mv^{2}}{2r} = 2\cdot\frac{mv^{2}}{r} = \boxed{2F_{d}}[/tex]
Odp. a) wzrośnie 2 razy.
2.
[tex]F_{d} = \frac{mv^{2}}{r}\\\\v_1 =2v\\r_1 = 4r\\\\F_{d_1} = \frac{m(2v)^{2}}{4r} = \frac{4mv^{2}}{4r} = \frac{mv^{2}}{r} = \boxed{F_{d}}[/tex]
Odp. e) nie zmieni się.