ROZWIAZYWANIE RÓWNAŃ - DAM NAJJJJ
a)
[tex] \frac{x - 2}{3} = \frac{2x + 1}{4} [/tex]
b)
[tex] \frac{3x + 2}{2x - 2} = \frac{2}{3} [/tex]
c)
[tex] \frac{6x - 1}{x + 1} = \frac{2.3}{1.2} [/tex]