Odpowiedź:
[tex]\frac{5}{12}a+2.5=4\frac{2}{3}\\\\\frac{5}{12}a+2.5=\frac{14}{3}\;\;\;\;\;\;\;/-\frac52\\\\\frac{5}{12}a=\frac{13}{6}\;\;\;\;\;\;\;/\cdot \frac{12}{5}\\\\\boxed{a=5.2}[/tex]
spr.:
[tex]\frac{5}{12}\cdot5.2+2.5=4\frac{2}{3}\\4\frac23=4\frac23[/tex]
OK
