Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]\sqrt{6} ^{2} +h^{2} =6^{2} \\6+h^{2}=36\\ h^{2} =30\\h=\sqrt{30} \\\\\\\\\sqrt{30} ^{2}+a^{2}=7^{2} \\30+a^{2}=49\\ a^{2}=19\\ a=\sqrt{19}[/tex]
[tex](3\sqrt{2})^{2}+12^{2} =c^{2} \\18+144=c^{2} \\162=c^{2} \\9\sqrt{2} =c \\\\\\b=9\sqrt{2} - 5,2\sqrt{2} =3,8\sqrt{2} \\b=3,8\sqrt{2}[/tex]
