Odpowiedź:
A = (0 , 4 ) , S = (- 2 , 2 ) , B = (xb , yb)
xa = 0 , xs = - 2 , ya = 4 , ys = 2
xs = (xa + xb)/2
2xs = xa+ xb
xb = 2xs - xa = 2 * ( -2) - 0 = - 4
ys = (ya + yb)/2
2ys = ya+ yb
yb = 2ys - ya= 2 * 2 - 4 = 4 - 4 = 0
B = ( - 4 , 0 )
IABI = √[(xb - xa)² + (yb - ya)²] = √[(- 4 - 0)² + ( 0 - 4)²] = √[(- 4)² + (- 4)²]=
= √(16 + 16) = √(16 * 2) = 4√2