Odpowiedź:
Pole trójkąta równobocznego = (a2√3)/4
a = 5
P = (5*5√3)/4
P = (25√3)/4
Obw = 3a
Obw = 15
32 + h2 = 52
9 + h2 = 25
h2 = 25 – 16
h2 = √16
h = 4
a = 6
P = (a*h)/2
P = (6*4)/2
P = 12
Obw = 6+5+5
Obw = 16
x2 + 4√3 2 = 92
x2 + 16 * 3 = 81
x2 + 48 = 81
x2 = 81 – 48
x2 = 33
x = √33
P = (a*h)/2
P = (√33* 4√3)/2
P = √33 * 2√3
P = 2√(33*3)
P = 2√99
Obw = 9 + 4√3 + √33
Szczegółowe wyjaśnienie:
