[tex] \frac{3 - x}{2} = \frac{1}{3} | \times 6 \\ 3(3 - x) = 2 \\ 9 - 3x = 2 | + 3x \\ 9 = 2 + 3x | - 2 \\ 3x = 7 | \div 3 \\ x = \frac{7}{3}[/tex]
Sprawdzenie
[tex] \frac{3 - \frac{7}{3} }{2} = \frac{1}{3} \\ (3 - \frac{7}{3} ) \div 2 = \frac{1}{3} \\ \frac{2}{3} \div 2 = \frac{1}{3} \\ \frac{2}{3} \times \frac{1}{2} = \frac{1}{3} \\ \frac{1}{3} = \frac{1}{3} \\ L = P[/tex]
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Zatem
[tex] \huge{x = \frac{7}{3} }[/tex]
