Odpowiedź :
a)
[tex]4y + y + 5 + 2x + x + 2 = \\ = 5y + 7 + 3x[/tex]
Fałsz
b)
[tex] \frac{(2x + 4y) \times (2y - 4)}{2} = \frac{4xy - 8x + 8 {y}^{2} - 16y}{2} = 2xy - 4x + 4 {y}^{2} - 8y[/tex]
Fałsz
a)
[tex]4y + y + 5 + 2x + x + 2 = \\ = 5y + 7 + 3x[/tex]
Fałsz
b)
[tex] \frac{(2x + 4y) \times (2y - 4)}{2} = \frac{4xy - 8x + 8 {y}^{2} - 16y}{2} = 2xy - 4x + 4 {y}^{2} - 8y[/tex]
Fałsz