[tex]\frac{4x^2-9}{2x^2-3x}:\frac{15+10x}{3x^2}=\frac{(2x-3)(2x+3)}{x(2x-3)}*\frac{3x^2}{5(2x+3)} =\frac{3x}{5}[/tex]
[tex]\frac{x^2+x-6}{x+5}:\frac{x-2}{x^2-2x-15} =\frac{x^2+3x-2x-6}{x+5} *\frac{x^2+5x-3x-15}{x-2} =\frac{x(x+3)-2(x+3)}{x+5} *\frac{x(x+5)-3(x+5)}{x-2} =(x+3)(x-3)=x^2-9[/tex]
