Odpowiedź:
A.
[tex] {76}^{o} + 3 \alpha + \alpha = {180}^{o} [/tex]
[tex]4 \alpha = {180}^{o} - {76}^{o} [/tex]
[tex]4 \alpha = {104}^{o} [/tex]
[tex] \alpha = {26}^{o} [/tex]
B.
[tex] \alpha + {83}^{o} + 2 \alpha + {10}^{o} = {180}^{o} [/tex]
[tex]3 \alpha = {180}^{o} - {93}^{o} [/tex]
[tex]3 \alpha = {87}^{o} [/tex]
[tex] \alpha = {29}^{o} [/tex]
C.
[tex]{80}^{o} + 2 \alpha + \alpha + {10}^{o} + \alpha = {360}^{o} [/tex]
[tex]4 \alpha = {180}^{o} - {90}^{o} [/tex]
[tex]4 \alpha = {270}^{o} [/tex]
[tex] \alpha = {67.5}^{o} [/tex]
D.
[tex] \alpha + \alpha - {30}^{o} + {135}^{o} + \alpha = {360}^{o} [/tex]
[tex]3 \alpha = {360}^{o} - {105}^{o} [/tex]
[tex] \alpha = {255}^{o} \div 3 = {85}^{o} [/tex]
E.
[tex] \alpha + {115}^{o} = {180}^{o} [/tex]
[tex] \alpha = {180}^{o} - {115}^{o} = {65}^{o} [/tex]
F.
[tex] {100}^{o} + {40}^{o} + \alpha = {180}^{o} [/tex]
[tex] \alpha = {180}^{o} - {140}^{o} = {40}^{o} [/tex]
