[tex]Dane:\\v_{o} = 10\frac{m}{s}\\f = 0,1\\v = 0\frac{m}{s}\\g = 10\frac{m}{s^{2}}\\Szukane:\\s = ?\\\\Rozwiazanie\\\\F = T\\\\m\cdot a = f\cdot F_{n}\\\\m\cdot a = f\cdot m\cdot g \ \ /:m\\\\a = f\cdot g\\\\a = 0,1\cdot10\frac{m}{s^{2}}\\\\\underline{a = 1\frac{m}{s^{2}}}[/tex]
[tex]v = v_{o}-at\\\\0 = v_{o}-at\\\\v_{o} = at \ \ /:a\\\\t = \frac{v_{o}}{a}\\\\t = \frac{10\frac{m}{s}}{1\frac{m}{s^{2}}}\\\\\underline{t = 10 \ s}[/tex]
[tex]s = v_{o}t -\frac{1}{2}at^{2}\\\\s = 10\frac{m}{s}\cdot10 \ s - \frac{1}{2}\cdot1\frac{m}{s^{2}}\cdot(10\frac{m}{s})^{2}\\\\s = 100 \ m - 50 \ m\\\\\boxed{s = 50 \ m}[/tex]
Odp. Przebyta przez łyżwiarza droga s = 50 m.