Odpowiedź:
[tex]I.\ \ \dfrac{125^7}{625^5}-5^0=\dfrac{(5^3)^7}{(5^4)^5}-1=\dfrac{5^2^1}{5^2^0}-1=5^{21-20}-1=5^1-1=5-1=4\\\\\\II.\ \ \dfrac{4^3\cdot8^2}{2^5\cdot2^0}:2^5=\dfrac{(2^2)^3\cdot(2^3)^2}{2^5\cdot1}:2^5=\dfrac{2^6\cdot2^6}{2^5}:2^5=\dfrac{2^1^2}{2^5}:2^5=2^{12-5}:2^5=\\\\\\=2^7:2^5=2^{7-5}=2^2=4[/tex]
[tex]III.\ \ \dfrac{2^1^0\cdot5^1^0}{5^2\cdot10000^2}=\dfrac{(2\cdot5)^1^0}{5^2\cdot(10^4)^2}=\dfrac{10^1^0}{5^2\cdot10^8}=\dfrac{10^{10-8}}{5^2}=\dfrac{10^2}{5^2}=\left(\dfrac{10}{5}\right)^2=2^2=4\\\\\\Odp.D[/tex]
