[tex]zad.12\\\\a)\\\\\dfrac{x}{3} +1=\dfrac{5}{6} +\dfrac{x}{2} ~~\mid \cdot 6\\\\2x+6=5+3x\\\\2x-3x=5-6\\\\-x=-1~~\mid \div (-1)\\\\x=1\\b)\\\\\dfrac{2x-3}{4} =\dfrac{1}{2} +x~~\mid \cdot 4\\\\2x-3=2+4x\\\\2x-4x=2+3\\\\-2x=5~~\mid \div (-2)\\\\x=-2,5\\\\c)\\\\\dfrac{x+2}{9} +\dfrac{x-1}{3} =1~~\mid \cdot 9\\\\x+2+3\cdot (x-1)=9\\\\x+2+3x-3=9\\\\4x-1=9\\\\4x=9+1\\\\4x=10~~\mid \div 4\\\\x=2,5\\\\[/tex]
[tex]d)\\\\\dfrac{2x+3}{5} =\dfrac{2-x}{3} +x~~\mid \cdot 15\\\\3\cdot (2x+3)=5\cdot (2-x)+15x\\\\6x+9=10-5x+15x\\\\6x+9=10+10x\\\\6x-10x=10-9\\\\-4x=1~~\mid \div (-4)\\\\x=-\dfrac{1}{4} \\\\x=-0,25[/tex]
