Cześć!
Rozwiąż równanie.
e)
[tex] - 2(2x - 1) = \frac{x}{3} \\ - 4x + 2 = \frac{x}{3} \\ - 12x + 6 = x \\ - 12x - x = - 6 \\ - 13x = - 6 \div | - 13 \\ \boxed{ x = \frac{6}{13} }[/tex]
f)
[tex] \frac{2}{5} (3 - x) = - 2 \\ 3 - x = - 5 \\ - x = - 5 - 3 \\ - x = - 8 \\ \boxed{x = 8}[/tex]
g)
[tex] \frac{3}{4} (2 - 3x) = - 6 \\ 2 - 3x = - 8 \\ - 3x = - 8 - 2 \\ - 3x = - 10 \div | - 3 \\ \boxed{x = \frac{10}{3} }[/tex]
h)
[tex] \frac{1}{5} (x - 3) = 9 - x \\ x - 3 = 45 - 5x \\ x + 5x = 45 + 3 \\ 6x = 48 \div | 6 \\ \boxed{x = 8}[/tex]
i)
[tex] \frac{0.6 + x}{2} = x + 1 \\ \frac{ \frac{3 {}}{5 } + x} {2} = x + 1 \\ \frac{ \frac{3 + 5x}{5} }{2} = x + 1 \\ \frac{3 + 5x}{10} = x + 1 \\ \\ 3 + 5x = 10x + 10 \\ 5x - 10x = 10 - 3 \\ - 5x = 7 \\ \boxed{x = - \frac{7}{5} }[/tex]
