daje najj plz o pomoc
ZLIKWIDUJ NIEWYMIERNOŚCI:
12√6/3√2
1+√3/2√2
3√5+5/4√3
OBLICZ:
3√2(2√3+5√6)
(3√2)⁵
(5√3)³

jak co to znak / to kreska ułamkowa ​



Odpowiedź :

Domi

Zlikwiduj niewymierność:

1)

[tex]\frac{12\sqrt{6}}{3\sqrt{2}}=\frac{4\sqrt{6}}{\sqrt{2}}=\boxed{4\sqrt{3}}[/tex]

2)

[tex]\frac{1+\sqrt{3}}{2\sqrt{2}}=\frac{1+\sqrt{3}}{2\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}=\frac{(1+\sqrt{3})\sqrt{2}}{2\sqrt{2}*\sqrt{2}}=\frac{\sqrt{2}+\sqrt{6}}{2*2}=\boxed{\frac{\sqrt{2}+\sqrt{6}}{4}}[/tex]

3)

[tex]\frac{3\sqrt{5}+5}{4\sqrt{3}}=\frac{3\sqrt{5}+5}{4\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}}=\frac{(3\sqrt{5}+5)\sqrt{3}}{4\sqrt{3}*\sqrt{3}}=\frac{3\sqrt{15}+5\sqrt{3}}{4*3}=\boxed{\frac{3\sqrt{15}+5\sqrt{3}}{12}}[/tex]

Oblicz:

1)

[tex]3\sqrt{2}(2\sqrt{3}+5\sqrt{6})=6\sqrt{6}+15\sqrt{12}=\boxed{6\sqrt{6}+30\sqrt{3}}[/tex]

2)

[tex](3\sqrt{2})^{5}=3^{5}*\sqrt{2}^{5}=243*4\sqrt{2}=\boxed{972\sqrt{2}}[/tex]

3)

[tex](5\sqrt{3})^{3}=5^{3}*\sqrt{3}^{3}=125*3\sqrt{3}=\boxed{375\sqrt{3}}[/tex]