[tex]\left \{ {{1=-3a+b} \atop {5=a+b /*(-1)}} \right. \\+\left \{ {{1=-3a+b} \atop {-5=-a-b}} \right. \\1-5=-3a-a\\-4=-4a /:(-4)\\1=a\\\\5=1+b /-1\\4=b\\\\y=x+4[/tex]
Odpowiedz na komentarz:
[tex]\left \{ {{0=-3a+b} \atop {4=a+b /*3}} \right. \\\left \{ {{0=-3a+b} \atop {12=3a+3b}} \right. \\0+12=b+3b \\12=4b /:4\\3=b\\\\4=a+3 /-3\\1=a\\\\y=x+3[/tex]
