[tex]3000g - 100\% \\ x - 10\% \\ \\ x = \frac{3000 \times 10}{100} = 300 \times 1 = 300g -sol[/tex]
Czyli
[tex]300g - 6\% \\ x - 100\% \\ \\ x = \frac{300 \times 100}{6} = \frac{30000}{6} = 5000g[/tex]
[tex]5000 - 3000 = 2000g = 2kg[/tex]
Należy dolać 2kg wody
