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Wzór na pole rombu
[tex]\text{P}=\frac{1}{2}\cdot e\cdot f[/tex]
a]
[tex]e=6 \ cm\\\\f=12 \ cm\\\\\text{P}=\frac{1}{2}\cdot6 \ cm\cdot12 \ cm=\frac{1}{2}\cdot72 \ cm^2=\boxed{36 \ cm^2}[/tex]
b]
[tex]e=8 \ cm\\\\f=6 \ cm\\\\\text{P}=\frac{1}{2}\cdot8 \ cm\cdot6 \ cm=\frac{1}{2}\cdot48 \ cm^2=\boxed{24 \ cm^2}[/tex]
c]
[tex]e=4 \ dm\\\\f=9 \ dm\\\\\text{P}=\frac{1}{2}\cdot4 \ dm\cdot9 \ dm=\frac{1}{2}\cdot36 \ dm^2=\boxed{18 \ dm^2}[/tex]
d]
[tex]e=2 \ dm=20 \ cm\\\\f=15 \ cm\\\\\text{P}=\frac{1}{2}\cdot20 \ cm\cdot15 \ cm=\frac{1}{2}\cdot300 \ cm^2=\boxed{150 \ cm^2}[/tex]
