Odpowiedź :
Odpowiedź:
C3H7COOH + NaOH--> C3H7COONa+ H2O
butanian sodu
C3H7COOH +5O2--> 4CO2 +4H2O --> całkowite
C3H7COOH + 3O2--> 4CO + 4H2O --> półspalanie
C3H7COOH + O2--> 4C + 4H2O --> niecałkowite
2C3H7COOH+2Na--->2C3H7COONa+H2
2C3H7COOH+K2O--->2C3H7COOK+H2O
C3H7COOH+NaOH--->C3H7COONa+H2O
C3H7COOH+5O2--->4CO2+4H2O
C3H7COOH+3O2--->4CO+4H2O
C3H7COOH+O2--->4C+4H2O