Odpowiedź:
a)
a = 9, b = 12 , c = 15
a - przyprostokątna leżąca na przeciw kąta α
b - przyprostokątna leżąca na przeciw kąta β
sinα= a/c = 9/15 = 3/5
cosα = b/c = 12/15 = 4/5
tgα = a/b = 9/12 = 3/4
ctgα = b/a= 12/9 = 4/3 = 1 1/3
sinβ = b/c = 12/15 = 4/5
cosβ = a/c = 9/15 = 3/5
tgβ = b/a= 12/9 =4/3 = 1 1/3
ctgβ = a/b= 9/12= 3/4
b)
a = √11
b= 5
c = 6
sinα= a/c = √11/6
cosα = b/c = 5/6
tgα = a/b = √11/5
ctgα = b/a = 5/√11 = 5√11/11
sinβ = b/c = 5/6
cosβ = a/c = √11/6
tgβ = b/a= 5/√11 =5√11/11
ctgβ = a/b= √11/5
c)
a = 7
b = 24
c = 25
sinα= a/c = 7/25
cosα = b/c= 24/25
tgα = a/b= 7/24
ctgα = b/a= 24/7 = 3 3/7
sinβ = b/c =24/25
cosβ = a/c = 7/25
tgβ = b/a =24/7 = 3 3/7
ctgβ= a/b = 7/24
