[tex]3\frac{4}{5} = \frac{19}{4}, \ \ bo \ \ 3\cdot5+4 = 19\\\\5\frac{1}{2} = \frac{11}{2}, \ \ bo \ \ 5\cdot2+1 = 11\\\\5\frac{1}{4} = \frac{21}{4}, \ \ bo \ \ 5\cdot4+1 = 21\\\\2\frac{2}{7} = \frac{16}{7}, \ \ bo \ \ 2\cdot7+2 =16[/tex]
Odpowiedź:
5 i 1/2=11/2 bo 5·2±1=11
5 i 1/4=21/4 bo 5·4±1=21
2 i 2/7=16/7 bo 2·7+2=16
Szczegółowe wyjaśnienie:
