Odpowiedź:
[tex]a)\\\\(3x-2)(x+1)=3x^2-5\\\\3x^2+3x-2x-2=3x^2-5\\\\3x^2+x-3x^2=-5+2\\\\x=-3\\\\\\b)\\\\(4-5x)(2+x)=-(4+5x^2)\\\\8+4x-10x-5x^2=-4-5x^2\\\\8-6x-5x^2=-4-5x^2\\\\-6x-5x^2+5x^2=-4-8\\\\-6x=-12\ \ |:(-6)\\\\x=2\\\\\\c)\\\\4x^2-2x=(2x+1)(2x-3)\\\\4x^2-2x=4x^2-6x+2x-3\\\\4x^2-2x=4x^2-4x-3\\\\4x^2-2x-4x^2+4x=-3\\\\2x=-3\ \ |:2\\\\x=-\frac{3}{2}\\\\x=-1\frac{1}{2}\\\\x=-1,5[/tex]
[tex]d)\\\\3x(2x+5)=(x+3)(6x+1)\\\\6x^2+15x=6x^2+x+18x+3\\\\6x^2+15x=6x^2+19x+3\\\\6x^2+15x-6x^2-19x=3\\\\-4x=3\ \ |:(-4)\\\\x=-\frac{3}{4}[/tex]
