Wysokość podstawy
[tex] {x}^{2} + (0.4 {)}^{2} = (0.5 {)}^{2} \\ {x}^{2} + 0.16 = 0.25 \\ {x}^{2} = 0.09 \\ x = \sqrt{0.09} \\ x = 0.3m[/tex]
Zatem pole podstawy
[tex] \frac{(0.2 + 1) \times 0.3}{2} = \frac{1.2 \times 0.3}{2} = \frac{0.36}{2} = 0.18 {m}^{2} [/tex]
Objętość jednego słupa
[tex]0.18 \times 8 = 1.44 {m}^{3} [/tex]
Objętość 100 słupów
[tex]1.44 \times 100 = \boxed{ \boxed{144 {m}^{3} }}[/tex]
