Odpowiedź :
14.
a)
[tex]Pp = \frac{ {2}^{2} \sqrt{3} }{4} = \sqrt{3} [/tex]
[tex]V = \frac{ \sqrt{3} \times 2 }{3} = \frac{2 \sqrt{3} }{3} [/tex]
b)
[tex]Pp = 1 \times 1 = 1[/tex]
[tex]V = \frac{1 \times 5}{3} = \frac{5}{3} = 1 \frac{2}{3} [/tex]
c)
[tex]Pp = 2 \times 2 = 4[/tex]
[tex]V = \frac{4 \times 2}{3} = \frac{8}{3} = 2 \frac{2}{3} [/tex]
d)
[tex]Pp = 6 \times \frac{ {0.5}^{2} \sqrt{3} }{4} = 6 \times \frac{0.25 \sqrt{3} }{4} = 3 \times \frac{0.25 \sqrt{3} }{2} = 3 \times 0.125 \sqrt{3} = 0.375 \sqrt{3} [/tex]
[tex]V = \frac{0.375 \sqrt{3} \times 2 \sqrt{3} }{3} = \frac{0.75 \sqrt{9} }{3} = \frac{0.75 \times 3}{3} = 0.75[/tex]
Odp.C
15.
a)
[tex] \frac{ {3}^{2} \sqrt{3} }{4} = \frac{9 \sqrt{3} }{4} {dm}^{2} [/tex]
Odp.A
b)
[tex] \frac{ \frac{9 \sqrt{3} }{4} \times x }{3} = 27 | \times 3 \\ \frac{9 \sqrt{3} }{4} \times x = 81 | \times 4 \\ 9 \sqrt{3} \times x = 324 | \div 9 \\ x \sqrt{3} = 36 | \div \sqrt{3} \\ x = \frac{36}{ \sqrt{3} } \\ x = \frac{36 \sqrt{3} }{3} \\ x = 12 \sqrt{3} dm[/tex]
Odp.D