1.
[tex]20 = \frac{8h}{2} | \times 2 \\ 40 = 8h | \div 8 \\ h = 5cm[/tex]
2
Obwód
[tex]3 \times 4 = 12cm[/tex]
Pole
[tex] \frac{ {4}^{2} \sqrt{3} }{4} = \frac{16 \sqrt{3} }{4} = 4 \sqrt{3} {cm}^{2} [/tex]
