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14. Zapisz równania reakcji pomiędzy kwasami karboksylowymi i alkoholami monohydroksylowymi tworzącymi estry do czterech atomów węgla w cząsteczce.



Odpowiedź :

Słodkamalina13

HCOOH+CH3OH--st. H2SO4--->HCOOCH3+H2O

HCOOH+C2H5OH--st. H2SO4--->HCOOC2H5+H2O

HCOOH+C3H7OH--st. H2SO4--->HCOOC3H7+H2O

HCOOH+C4H9OH--st. H2SO4--->HCOOC4H9+H2O

CH3COOH+CH3OH--st. H2SO4--->CH3COOCH3+H2O

CH3COOH+C2H5OH--st. H2SO4--->CH3COOC2H5+H2O

CH3COOH+C3H7OH--st. H2SO4--->CH3COOC3H7+H2O

CH3COOH+C4H9OH--st. H2SO4--->CH3COOC4H9+H2O

C2H5COOH+CH3OH--st. H2SO4--->C2H5COOCH3+H2O

C2H5COOH+C2H5OH--st. H2SO4--->C2H5COOC2H5+H2O

C2H5COOH+C3H7OH--st. H2SO4--->C2H5COOC3H7+H2O

C2H5COOH+C4H9OH--st. H2SO4--->C2H5COOC4H9+H2O

C3H7COOH+CH3OH--st. H2SO4--->C3H7COOCH3+H2O

C3H7COOH+C2H5OH--st. H2SO4--->C3H7COOC2H5+H2O

C3H7COOH+C3H7OH--st. H2SO4--->C3H7COOC3H7+H2O

C3H7COOH+C4H9OH--st. H2SO4--->C3H7COOC4H9+H2O

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