Odpowiedź:
[tex]A.\\\\2x+2\frac{1}{3}=1\\\\L=2\cdot(-\frac{2}{3})+2\frac{1}{3}=-\frac{4}{3}+\frac{7}{3}=\frac{3}{3}=1\\\\P=1\\\\L=P\\\\Liczba\ \ -\frac{2}{3}\ \ spelnia\ \ to\ \ r\'ownanie\\\\\\B.\\\\6x-8=-4\\\\L=\not6^2\cdot(-\frac{2}{\not3_{1}})-8=-4-8=-12\\\\P=-4\\\\L\neq P\\\\Liczba\ \ -\frac{2}{3}\ \ nie\ \ spelnia\ \ tego\ \ r\'ownania[/tex]
[tex]C.\\\\3x^3+\frac{1}{9}=1\\\\L=3\cdot(-\frac{2}{3})^3+\frac{1}{9}=\not3^1\cdot(-\frac{8}{\not27_{9}})+\frac{1}{9}=-\frac{8}{9}+\frac{1}{9}=-\frac{7}{9}\\\\P=1\\\\L\neq P\\\\Liczba\ \ -\frac{2}{3}\ \ nie\ \ spelnia\ \ tego\ \ r\'ownania\\\\\\D.\\\\3x^2-\frac{1}{3}=1\\\\L=3\cdot(-\frac{2}{3})^2-\frac{1}{3}=\not3^1\cdot\frac{4}{\not9_{3}}-\frac{1}{3}=\frac{4}{3}-\frac{1}{3}=\frac{3}{3}=1\\\\P=1\\\\L=P\\\\Liczba\ \ -\frac{2}{3}\ \ spelnia\ \ to\ \ r\'ownanie[/tex]
[tex]Odp.\ \ Liczba\ \ -\frac{2}{3}\ \ spelnia\ \ r\'ownanie\ \ A\ \ i\ \ D[/tex]
