[tex]x^{3}-3x^{2}=4x\\\\x^{3}-3x^{2}-4x = 0\\\\x(x^{2}-3x-4) = 0\\\\\boxed{x_{o} = 0}\\\\lub\\\\x^{2}-3x-4 = 0\\\\a = 1, \ b = -3, \ c = -4\\\\\Delta = b^{2}-4ac = (-3)^{2}-4\cdot1\cdot(-4) = 9+16 = 25\\\\\sqer{\Delta} = \sqrt{25} = 5[/tex]
[tex]x_1 = \frac{-b-\sqrt{\Delta}}{2a} = \frac{3-5}{2\cdot1} = \frac{-2}{2} = \boxed{-1}\\\\x_2 = \frac{-b+\sqrt{\Delta}}{2a} = \frac{3+5}{2} = \frac{8}{2} = \boxed{4}[/tex]
[tex]\underline{x\in \{-1, 0, 4 \}}[/tex]
