Odpowiedź:
[tex]\begin{cases}\frac{x-y}{2}+0,5=\frac{2x+y}{3}\ \ /\cdot6\\\frac{x-1}{2}=\frac{y+1}{4}\end{cases}\\\\\\\begin{cases}3(x-y)+3=2(2x+y)\\4(x-1)=2(y+1)\end{cases}\\\\\\\begin{cases}3x-3y+3=4x+2y\\4x-4=2y+2\end{cases}\\\\\\\begin{cases}3x-3y-4x-2y=-3\\4x-2y=2+4\end{cases}\\\\\\\begin{cases}-x-5y=-3\ \ /\cdot4\\4x-2y=6\end{cases}\\\\\\+\begin{cases}-4x-20y=-12\\4x-2y=6\end{cases}\\----------\\-22y=-6\ \ /:(-22)\\\\y=\frac{6}{22}\\\\y=\frac{3}{11}[/tex]
[tex]-x-5\cdot\frac{3}{11}=-3\\\\-x-\frac{15}{11}=-3\\\\-x=-3+\frac{15}{11}\\\\-x=-\frac{33}{11}+\frac{15}{11}\\\\-x=-\frac{18}{11}\ \ /\cdot(-1)\\\\x=\frac{18}{11}\\\\\\\begin{cases}x=\frac{18}{11}\\y=\frac{3}{11}\end{cases}[/tex]
