a)
[tex] {x}^{2} = {4}^{2} + {3}^{2} \\ {x}^{2} = 16 + 9 \\ x = \sqrt{25} \\ x = 5[/tex]
Obwód
[tex]10 + 5 + 13 + 4 = 32[/tex]
Pole
[tex] \frac{(10 + 13) \times 4}{2} = \frac{23 \times 4}{2} = 23 \times 2 = 46[/tex]
b)
[tex] {h}^{2} + {3}^{2} = {4}^{2} \\ {h}^{2} + 9 = 16 \\ {h}^{2} = 7 \\ h = \sqrt{7} [/tex]
Obwód
[tex]2(7 + 4) = 2 \times 11 = 22[/tex]
Pole
[tex]7 \times \sqrt{7} = 7 \sqrt{7} [/tex]
