[tex](3a+4):(-\frac{1}{5}) = (3a+4)\cdot(-5) = 3a\cdot(-5) + 4\cdot(-5) =\underline{ -15a-20}\\\\-15a = (6-21)a\\\\-20 = -12-8\\\\\\\underline{(3a+4):(-\frac{1}{5}) =\boxed{ 6-21}a+\boxed{-12-8}}[/tex]
