Odpowiedź:
[tex]a)\ \ a:b\ \ \ \ dla\ \ a=3\frac{1}{9}\ \ ,\ \ b=4\frac{2}{3}\\\\\\a:b=3\frac{1}{9}:4\frac{2}{3}=\frac{28}{9}:\frac{14}{3}=\frac{\not28^2}{\not9_{3}}\cdot\frac{\not3^1}{\not14_{1}}=\frac{2}{3}\\\\\\\\b)\ \ a^3-b\ \ \ \ dla\ \ a=-0,1\ \ ,\ \ b=1\\\\\\a^3-b=-0,1^3-1=-0,001-1=-1,001[/tex]