Odpowiedź:
[tex]A(-5,0)\ \ ,\ \ B(1,6)\\\\y=ax+b\\\\\\\begin{cases}0=-5a+b\ \ /\cdot(-1)\\6=a+b\end{cases}\\\\\\+\begin{cases}0=5a-b\\6=a+b\end{cases}\\-------\\6=6a\\\\6a=6\ \ /:6\\\\a=1\\\\\\6=1+b\\\\6-1=b\\\\5=b\\\\b=5\\\\\\\underline{y=x+5}[/tex]
