Odpowiedź:
[tex] log_{4}(1 \frac{3}{13} ) - log_{4}(3 \frac{1}{2} ) - log_{4}( \frac{1}{91} ) = log_{4}( \frac{16}{13} ) - log_{4}( \frac{7}{2} ) - log_{4}( \frac{1}{91} ) = log_{4}( \frac{16}{13} \times \frac{2}{7} \times 91 ) - log_{4}( \frac{1}{91} ) = log_{4}32 = log_{ {2}^{2} }( {2}^{5} ) = \frac{5}{2} [/tex]
