[tex]Dane:\\s = 4,9 \ km = 4 \ 900 \ m\\t = 15 \ min=\frac{15}{60} \ h = 0,25 \ h = 15\cdot60 \ s = 900 \ s \\Szukane:\\v = ?\\\\v = \frac{s}{t}[/tex]
[tex]a) \ v = \frac{4,9 \ km}{15 \ min} = 0,32(6)\frac{km}{min} \approx\boxed{0,33\frac{km}{min}}\\\\b) \ v = \frac{4,9 \ km}{0,25 \ h} =\boxed{ 19,6\frac{km}{h}}\\\\c) \ v = \frac{4900 \ m}{900 \ s}\approx\boxed{5,44\frac{m}{s}}[/tex]
