Odpowiedź:
a)
[tex] \sqrt{12} + 5 \sqrt{3} = \sqrt{4 \times 3} + 5 \sqrt{3} = 2 \sqrt{3} + 5 \sqrt{3} = 7 \sqrt{3} [/tex]
b)
[tex]2 \sqrt{48} + 2 \sqrt{3} = 2 \sqrt{16 \times 3} + 2 \sqrt{3} = 8 \sqrt{3 }+ 2 \sqrt{3} = 10 \sqrt{3} [/tex]
c)
[tex]3 \sqrt{20 } + \sqrt{5} = 3 \sqrt{4 \times 5} + \sqrt{5} = 6 \sqrt{5} + \sqrt{5} = 7 \sqrt{5} [/tex]
d)
[tex] \sqrt{18} - 2 \sqrt{8} = \sqrt{9 \times 2} - 2 \sqrt{4 \times 2} = 3 \sqrt{2} - 4 \sqrt{2} = - \sqrt{2} [/tex]
e)
[tex] \sqrt{90} + \sqrt{40} + \sqrt{250} = \sqrt{9 \times 10} + \sqrt{4 \times 10} + \sqrt{25 \times 10} = 3 \sqrt{10} + 2 \sqrt{10} + 5 \sqrt{10} = 10 \sqrt{10} [/tex]
f)
[tex] \sqrt[3]{40} + \sqrt[3]{135} = \sqrt[3]{8 \times 5} + \sqrt[3]{27 \times 5} = 2 \sqrt[3]{5} + 3 \sqrt[3]{5} = 5 \sqrt[3]{5} [/tex]
