Odpowiedź:
[tex](-3-\sqrt{3}x)^3=(-3)^3-3\cdot(-3)^2\cdot\sqrt{3}x+3\cdot(-3)\cdot(-\sqrt{3}x)^2-(\sqrt{3}x)^3=\\\\=-27-3\cdot9\cdot\sqrt{3}x-9\cdot3x^2-\sqrt{27}x^3=-27-27\sqrt{3}x-27x^2-\sqrt{9\cdot3}x^3=\\\\=-27-27\sqrt{3}x-27x^2-3\sqrt{3}x^3\\\\\\Zastosowany\ \ wz\'or\\\\(a-b)^3=a^3-3a^2b+3ab^2-b^3[/tex]
