Odpowiedź :
Szczegółowe wyjaśnienie:
2x^2 -14x = x^2 -3x
x^2 -11x =0
x(x -11)= 0
x=0 oraz x= 11
[tex]2x(x-7) = x(x-3)\\\\2x^{2}-14x = x^{2}-3x\\\\2x^{2}-x^{2}-14x+3x = 0\\\\x^{2}-11x = 0\\\\x(x-11) = 0\\\\x = 0 \ \vee \ x-11 = 0\\\\x = 0 \ \vee \ x = 11\\\\x \in \{0,11\}[/tex]