Z twierdzenia Pitagorasa
[tex] {x}^{2} + {y}^{2} = (3 \sqrt{7} {)}^{2} \\ (3 \sqrt{3} {)}^{2} + {y}^{2} = (3 \sqrt{7} {)}^{2} \\ 9 \times 3 + {y}^{2} = 9 \times 7 \\ 27 + {y}^{2} = 63 \\ {y}^{2} = 36 \\ y = \sqrt{36} \\ y = 6[/tex]
