[tex]\Delta = 12\\W = (p,q)\\i\\W = (4,3) \ \ \rightarrow \ \ p = 4, \ q = 3\\\\q = \frac{-\Delta}{4a}=\frac{-12}{4a} = \frac{-3}{a}\\i\\q = 3\\\\3 = \frac{-3}{a} \ \ \ |\cdot a\\\\3a =-3 \ \ \ /:3\\\\\underline{a = -1}[/tex]
Skorzystam z postaci kanonicznej funkcji kwadratowej:
[tex]f(x) = a(x-p)^{2}+q\\\\f(x) = -(x-4)^{2}+3 = -(x^{2}-8x+16)+3 = -x^{2}+8x-16+3\\\\\boxed{f(x) = -x^{2}+8x-13} \ - \ wzor \ funkcji \ w \ postaci \ ogolnej\\\\f(x) = ax^{2}+bx+c\\\\\boxed{a = -1}\\\boxed{b = 8}\\\boxed{c = -13}[/tex]
