Odpowiedź :
[tex]\frac{2x+3}{2} =\frac{5x-3}{3} /*2,*3\\\\(2x+3)*3=(5x-3)*2\\\\6x+9=10x-6/-9,-10x\\\\6x-10x=-6-9\\\\-4x=-15/:(-4)\\\\x=\frac{15}{4} \\\\x=3\frac{3}{4}[/tex]
[tex]\frac{2x+3}{2} =\frac{5x-3}{3} /*2,*3\\\\(2x+3)*3=(5x-3)*2\\\\6x+9=10x-6/-9,-10x\\\\6x-10x=-6-9\\\\-4x=-15/:(-4)\\\\x=\frac{15}{4} \\\\x=3\frac{3}{4}[/tex]