Odpowiedź:
[tex]\frac{-3+x}{2}=\frac{2x-7}{5}\\\\5(-3+x)=2(2x-7)\\\\-15+5x=4x-14\\\\5x-4x=-14+15\\\\\boxed{x=1} \ (\text{Odp}. \ \text{A})[/tex]
[tex]\frac{-3+x}{2} = \frac{2x-7}{5} \ \ |\cdot10\\\\5(-3+x) = 2(2x-7)\\\\-15+5x = 4x-14\\\\5x-4x = -14+15\\\\\boxed{x = 1}\\\\\underline{Odp. \ A. \ 1}[/tex]
