a)
[tex]a - bok[/tex]
Pole trójkąta
[tex] \frac{ \frac{1}{2} a \times \frac{1}{2} a}{2} = \frac{1}{4} {a}^{2} \times \frac{1}{2} = \frac{1}{8} {a}^{2} [/tex]
Pole kwadratu
[tex]a \times a = {a}^{2} [/tex]
PRAWDA
b)
[tex]d - przekatna[/tex]
[tex]d = a \sqrt{2} [/tex]
Pole trójkąta DBC
[tex] \frac{a \sqrt{2} \times \frac{1}{2}a \sqrt{2} }{2} = \frac{ \frac{1}{2} {a}^{2} \sqrt{4} }{2} = \frac{1}{2} { a }^{2} \times 2 \times \frac{1}{2} = \frac{1}{2} {a}^{2} [/tex]
Pole trapezu
[tex] \frac{1}{2} {a}^{2} - \frac{1}{8} {a}^{2} = \frac{4}{8} {a}^{2} - \frac{1}{8} {a}^{2} = \frac{3}{8} {a}^{2} [/tex]
PRAWDA
