Odpowiedź:
zadanie 17
[tex] {4}^{10} = ( {2}^{2 )^{10} } ) = {2}^{20} [/tex]
[tex] {8}^{4} = ({2}^{3})^{4} = {2}^{12} [/tex]
pary to I i C
II i B
zadanie 18
[tex] \frac{2 \sqrt{6} }{ \sqrt{2} } = \frac{2 \sqrt{3} \times \sqrt{2} }{ \sqrt{2} } = 2 \sqrt{3} [/tex]
[tex]3 \sqrt{12} + \sqrt{27} = 3 \times 2 \sqrt{3} + 3 \sqrt{3} = 6 \sqrt{3} + 3 \sqrt{3} = 9 \sqrt{3} [/tex]
