1.
[tex]t_1 = 90^{o}C\\\\t_2 = 10^{o}C[/tex]
2.
[tex]t_1 = 90^{o}C \pm2^{o}C\\\\t_2 = 10^{o}C\pm2^{o}C[/tex]
3.
[tex]T_1 = (90+273)K = 363 \ K\\\\T_2 = (10+273)K = 284 \ K[/tex]
4.
[tex]t_{F_1} = (\frac{9}{5}\cdot90^{o}C + 32)^{o}F = 194^{o}F \\\\t_{F_2} = (\frac{9}{5}\cdot10^{o}C + 32) = 50^{o}F[/tex]
5.
[tex]\Delta ^{o}C = 90^{o} -10^{o}C = 80^{o}C\\\\\Delta K = 363 \ K - 283 \ K = 80 \ K\\\\\Delta ^{o}F = 194^{o}F - 50^{o}F = 144^{o}F[/tex]
