Odpowiedź:
[tex]( \sin60^{o} + \tg {45}^{o} {)}^{2} - 2 \cos {30}^{o} = ( \frac{ \sqrt{3} }{2} + 1 {)}^{2} - 2 \times \frac{ \sqrt{3} }{2} = \frac{3}{4} + \sqrt{3} + 1 - \sqrt{3} = 1 \frac{3}{4} [/tex]