[tex]2+x\neq 0~~\Rightarrow ~~x\neq -2,~~x\neq 0~~\Rightarrow~~D=R-\{ -2,0\}\\\\\dfrac{4}{x} =\dfrac{3}{2+x} \\\\4\cdot (2+x)=3\cdot x\\\\8+4x=3x\\\\4x-3x=-8\\\\x=-8~~\land~~x\in D ~~\Rightarrow ~~x=-8\\\\Sprawdzam:\\\\\dfrac{4}{x} =\dfrac{3}{2+x}~~\land~~x=-8\\\\L=\dfrac{4}{-8}=-\dfrac{1}{2} \\\\P=\dfrac{3}{2-8}=\dfrac{3}{-6} =-\dfrac{1}{2} \\\\L=P[/tex]
