Odpowiedź:
zad.1
a)
[tex]Pp = 2(ab + ac + bc) = 2(3 \times 4 + 3 \times 5 + 4 \times 5) = \\ 2(12 + 15 + 20) = 2 \times 47 = 94 \: {cm}^{2} \\ \\ V= abc = 3 \times 4 \times 5 = 60 \: {cm}^{3} [/tex]
b)
[tex]Pp = 2 \times {6}^{2} + 4 \times 6 \times 7 = 72 + 168 = 240 {cm}^{2} \\ V = {6}^{2} \times 7 = 36 \times 7 = 252 {cm}^{3} [/tex]
zad.2
[tex]V = \frac{(4 + 12)6}{2} \times 10 = 480 {cm}^{3} [/tex]
zad.3
[tex]h_{b} = \sqrt{ {15}^{2} - {5}^{2} } = \sqrt{225 - 25} = \sqrt{200} = 10 \sqrt{2 } \\ Pp = \frac{3 \times {10}^{2} \sqrt{3} }{2} + 6 \times \frac{1}{2 } \times 10 \times 10 \sqrt{2} = 150 \sqrt{3} + 300 \sqrt{2} = 150( \sqrt{3} + 2 \sqrt{2} ) \: {cm}^{2} [/tex]
