[tex] \sqrt{0.(4)} = \sqrt{ \frac{4}{9} } [/tex]
[tex] \sqrt{1.(7) } = \sqrt{ \frac{16}{9} } [/tex]
no i jest wzór, że
[tex] \sqrt{ \frac{a}{b} } = \frac{ \sqrt{a} }{ \sqrt{b} } [/tex]
czyli
[tex] \sqrt{ \frac{4}{9} } = \frac{ \sqrt{4} }{ \sqrt{9} } = \frac{2}{3} [/tex]
i
[tex] \sqrt{ \frac{16}{9} } = \frac{ \sqrt{16} }{ \sqrt{9} } = \frac{4}{3} [/tex]
no i teraz mozemy to dodać
[tex] \frac{2}{3} + \frac{4}{3} = \frac{6}{3 } = 2[/tex]
pozdro
