[tex]Dane:\\F = 800 \ N\\s = 3 \ m\\t = 2 \ min = 2\cdot60 \ s = 120 \ s\\Szukane:\\P = ?\\\\Rozwiazanie\\\\W = F\cdot s = 800 \ N\cdot3 \ m = 2 \ 400 \ J\\\\P = \frac{W}{t}\\\\P = \frac{2400 \ J}{120 \ s}\\\\\boxed{P = 20 \ W}[/tex]
Odp. Moc tego silnika ma wartość 20 W (watów).
